1. The problem statement, all variables and given/known data draw transition/excitatiob table for state machine with jk flip flop. using the tables given 2. Relevant equations excitation table for jk ff q qn j l 000x 011x 10x1 11x0 x is dont care table ps ns ns x=0 x=1 00 10 10 01 10 11 3. The attempt at a solution Im just not sure how to do this. I know how to do it for a d ff and when they give a circuit but no idea about this the solution is x=0 x=1 q1q0 Q1Q0 J1K1 J0K0 Q1Q0 J1K1 J0K0 00 10 1x 0x 10 1x 0x 01 10 1x x1 11 1x x0 I know how they get the q1q0 and Q1Q0 but no idea how they get the jk it said to use excitation table for jk but dont see how that has anything to do with this.