- 18

- 0

[tex]V_{peak} cos \omega t - L\frac{di}{dt} - IR - \frac{Q}{C} = 0[/tex]

- OR -

[tex]V_{peak} cos \omega t = L\frac{d^{2}Q}{dt^{2}} + \frac{dQ}{dt}R + \frac{Q}{C}[/tex]

I have never done second order differential equations, so right now I am stuck if I want to solve for Q(t) or I(t).

-Ataman