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negation

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## Homework Statement

You're atop a building of height, h, and a friend is poised to drop a ball from a window at h/2. Find an expression for the speed at which you should simultaneously throw a ball downward, so the two hit the ground at the same time.

## Homework Equations

None

## The Attempt at a Solution

1)H = vit + 0.5gt^2

t1 = SQRT[(H - vit)/-4.9ms^-2]

2)H/2 = vit + 0.5gt^2

t2 = SQRT[(H/2-vit)/-4.9ms6-2]

t2 is the time taken for ball to fall from H/2 to ground

t2=t1

so,

set t1= SQRT[(H - vit)/-4.9ms^-2] to be equals to t2

therefore,

SQRT[(H/2-vit)/-4.9ms6-2] = SQRT[(H - vit)/-4.9ms^-2]

vi = [H - 4.9ms^-2(h/2-vit)/(-4.9ms^-2)]/t

Could someone give me a let up?

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