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Dropping a golf ball

  1. Aug 28, 2007 #1
    A golf ball released from a height of 1.76 m above a concrete floor, bounces back to a height of 0.80 m. If the ball is in contact with the floor for 4.62 ms, what is the magnitude of the average acceleration a of the ball while it is in contact with the floor?

    I'm not sure how to start this. I was thinking of this equation:

    4.7x^2-1.76x

    I think
     
  2. jcsd
  3. Aug 28, 2007 #2

    Astronuc

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    Staff: Mentor

    Why?

    What is the velocity of the ball when it hits the floor?

    What is the initial velocity of the ball in order to achieve an altitude of 0.80 m?

    What is the change in velocity?

    What is the average acceleration thereof?
     
  4. Aug 28, 2007 #3
    I'm not sure, I lifted this question off my homework. I'm pretty stumped on this question.
     
  5. Aug 28, 2007 #4

    learningphysics

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    Homework Helper

    What is the velocity right before it hits the ground? What is the velocity right immediately after it bounces?
     
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