(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

27^{x+1}=3^{2x+1}

3. The attempt at a solution

log(27^{x+1})=log(3^{2x+1})

(x+1)log(27)=(2x+1)log(3)

2x+1=[itex]\frac{(x+1)log(27)}{log(3)}[/itex]

[itex]\frac{2x+1}{x+1}=\frac{log(27)}{log(3)}[/itex]

x=-2

I'm wondering how I would have continued solving this for the exact answer if [itex]\frac{log(27)}{log(3)}[/itex] had turned out to be irrational?

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# Homework Help: Dumb log question

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