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For example, if a rock is thrown in the water with the acceleration of gravity on a 15.3m high cliff, can final velocity be equal to 17.32m/s or is that incorrect?

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- Thread starter harujina
- Start date

- #1

- 77

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For example, if a rock is thrown in the water with the acceleration of gravity on a 15.3m high cliff, can final velocity be equal to 17.32m/s or is that incorrect?

- #2

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s=ut+1/2at^2

0=-4.9t^2+15.3

t = 1.77

v=u+at

= 0-9.8x1.77

= -17.35m/s

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Khashishi

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meBigGuy

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AlephZero

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For your information, you cannot directly compare values with different units.

I think the OP is asking about the final velocity and the average velocity (total distance/total time).

Of course the final velocity can be bigger than the average. The average of any set of numbers is always somewhere in between the biggest and smallest numbers, unless all the numbers are the same (which would mean the velocity was constant).

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