(adsbygoogle = window.adsbygoogle || []).push({}); Simple Projectile Question

there is a volleyball net 2.24m high (the court is 9m by 9m on both sides), and you hit the ball while being 3m in the air, you are 8m away from the net, if the initial velocity is horizontal find

A)what minimum velocity must the ball have to clear the top of the net

B)what maximum velocity can it have if the ball is to strike the the back line on the other side of the net?

Work.....

V0 = ?

X-X0 = 8m

Y-Y0 = 0.76m

(theta) = 84.57

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Vy2 = -2g(y-y0)

Vy = 3.76m/s

Vy = V0sin(theta) - gt

Vy/-g = t

t = 0.38

X-X0 = V0x(t)

8m = V0x(0.38s)

V0x = 21.05 m/s???not likely

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# Dumb questioncan someone help me?

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