A basketball player dunks the ball and momentarily hangs from the rm of the basket. Assume that the player can be considered as a 95.0kg point mass at a height of 2.0m above the floor. If the basket rim has a spring constant of 7.4 x 10^3 N/m, by how much does the player displace the rim from the horizontal position?
Conservation of Energy
The Attempt at a Solution
I set the initial instance to be the bottom, where Eg and Ee would be 0. The final instance to be at the top where he is holding onto the rim. There Eg and Ee are present.
0 = Eg' + Ee'
0 = (m)(g)(h) + 1/2(k)(x)^2
-(m)(g)(h)*2 / k = x^2
Woops, I ran into a negative square root. What am I doing wrong here?