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Dx/dt = dv or just v

  1. Jun 28, 2005 #1
    Does dx/dt = dv or just v(avg.)?

  2. jcsd
  3. Jun 28, 2005 #2


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    There's no average,it's the function itself.

    [tex]v(t)=:\frac{dx(t)}{dt} [/tex]

    We call it instant velocity,as we can use the definition of the derivative.We compute the "x" comp.of the velocity at the moment of time [itex]t_{0} [/itex] by

    [tex] v(t_{0})=:\lim_{t\rightarrow t_{0}} \frac{x(t)-x(t_{0})}{t-t_{0}} [/tex]

    or simply by plugging the time value in the velocity function itself.

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