1. The problem statement, all variables and given/known data http://members.shaw.ca/code/cylinder.JPG 2. Relevant equations I denote the top of the ceiling to the top of cylinder A la. I denote the top most small pulley above A to the larger pulley bottom directly above A as Xa I denote the distance from the pulley that changes the direction of the rope to the ceiling la' I denote the top most pulley above B to the smaller pulley bottom directly above B as Xb I denote the top of the ceiling to the top of cylinder B as lb. I call upward motion -ve and downward +ve in the calculations. 3. The attempt at a solution (la-2xa) + (xa-la') + (lb-2xb) = C then I say l* is a constant so.. -2xa+xa-2xb=C now I differentiate to attain velocity -dXa/dt -2dxb/dt = const/dt = 0 -Va -2Vb=0 therefore Vb = -0.4m/s or 0.4m/s UP now i differentiate again to attain acceleration -dVa/dt -2dVb/dt =0 -Aa-2Ab=0 therefore Ab =-1m/s2 or 1m/s^2 UP Vba = Vb-Va = (-0.4 - 0.8m/s) = -1.2m/s or 1.2m/s UP Aba = Ab -Aa = (-1.2m/s^2 - 2m/s^2) = -3m/s^2 or 3m/s^2 UP Can anyone confirm that my initial labeling is correct, and also hopefully that my final answer is correct?