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## Homework Statement

A student is skateboarding down a ramp that is 5.9 m long and inclined at 12° with respect to the horizontal. The initial speed of the skateboarder at the top of the ramp is 2.3 m/s. Neglect friction and find the speed at the bottom of the ramp.

## Homework Equations

This is my steps:

As I dont know the weight of the student, I dont know the force. So I cant use F-ma

Vo=2.3

Vox= 2.3cos78°= 0.48

Voy= 2.3sin78°=2.25

t=0.32

ΔY (found by SOPHATOA) =Voy.t+1/2 a t^2

1.23= 2.25t+1/2(9.8) t^2

ΔX=Vox.t+1/2 a t^2

5.8=0.48(0.32)+1/2.a.(0.32)

ax=110.3

Vx=Vox+at

Vx=0.48+110.3(0.32)

Vx=35.8

Vy=Voy+at

Vy=2.25+9.8(0.32)

Vy=5.386

therefore the resultant of Vx and Vy is 36.2

## The Attempt at a Solution

my answer is wrong

I really need some help :D