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Dynamics 2/32

  1. Feb 8, 2012 #1
    Please help,

    A motorcycle patrolman starts from rest at A 5 seconds after a car, speeding at the constant rate of 124 km/h, passes point A. If the patrolman accelerates at the rate of 6.4 m/s2 until he reaches his maximum permissible speed of 147 km/h, which he maintains, calculate the distance s from point A to the point at which he overtakes the car.

    Thanks!
     
  2. jcsd
  3. Feb 9, 2012 #2

    tiny-tim

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    welcome to pf!

    hi varsitymsb5! welcome to pf! :wink:

    use the standard constant acceleration equations for each vehicle (you'll need t in one to be t+5 in the other) …

    show us what you get! :smile:
     
  4. Feb 9, 2012 #3
    v=vnot+at
    147/3.6=6.4t
    t=6.38s
    s(car)=124/3.6t'
    s(moto)=147/3.6(t'-5)

    I'm stuck and not sure what to do next.
     
  5. Feb 9, 2012 #4

    tiny-tim

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    sorry, i'm not following this at all :confused:

    rewrite the words of the question into equations
     
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