# Dynamics and Free Fall

1. Sep 16, 2007

### Jacobpm64

1. The problem statement, all variables and given/known data
A parachutist of mass 80 kg approaches the ground at 5 m/s. Suppose that when he hits the ground, he decelerates at a constant rate (while his legs buckle under him) over a distance of 1 m. What is the force the ground exerts on his feet during the deceleration?

2. Relevant equations
$$\vec{F} = m \vec{a}$$

3. The attempt at a solution

I think a lot of this information is extraneous. Isn't the force that the ground exerts on the parachutist going to be opposite his weight?

So, $$\vec{F} = mg = (80 * 9.8) = 784$$ N

I'm not sure about this because it seems odd that all of that extra information would be given if it is not needed.

2. Sep 16, 2007

### bob1182006

I think you're supposed to find the acceleration (decelleration in this case) before you find the force the ground exerts on him.

You're given a velocity, a distance, what equation can you use to determine the decelleration?

3. Sep 16, 2007

### Jacobpm64

So, let's see what I can do.

$$x_{0} = 1 m$$
$$v_{0} = 5 m/s$$
$$x = 0 m$$
$$v = 0 m/s$$

$$a(x-x_{0})=\frac{1}{2}(v^2 -v_{0}^2)$$

solving for a,

$$a = \frac{v^2-v_{0}^2}{2(x-x_{0})}$$

Plugging in the numbers,

$$a = \frac{(0)^2 - (5)^2}{2(0-1)}$$

$$a = 12.5 m/s^2$$

So, what do I do now, do I still factor in gravity?

4. Sep 16, 2007

### bob1182006

ok so decelleration is 12.5m/s^2 now you can use that a in order to find the force he exerts on the ground, and then the force the ground exerts on him.

5. Sep 16, 2007

### Jacobpm64

So,

$$F = ma = (80 * 12.5) = 1000 N$$