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Dynamics and Friction

  • Thread starter chs60815
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  • #1
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1. A 600 N physics student stands on a bathroom scale in an 814 kg (including the student) elevator that is supported by a cable. As the elevator starts moving, the scale reads 464 N .
1) Find the magnitude of the acceleration of the elevator.

2.F=ma ???

3.I tried to seperate into y and x equations and find the values but it didn't work.
 

Answers and Replies

  • #2
tiny-tim
Science Advisor
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welcome to pf!

hi chs60815! welcome to pf! :wink:
… 2.F=ma ???

3.I tried to seperate into y and x equations and find the values but it didn't work.
x ?? which way is this elevator going?? :confused:

F = ma should do it …

show us your full calculations, and then we'll see what went wrong! :smile:
 
  • #3
there is no need for x.
For the question you need to be clear on one thing. The scale just shows the amount of force you give it while standing.
 
  • #4
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No x axis interactions are happening.
Answer: 600N-X(force caused by elevator)=464N
x=136N=ma
136N/814kg=.167m/s^2
 
  • #5
No x axis interactions are happening.
Answer: 600N-X(force caused by elevator)=464N
x=136N=ma
136N/814kg=.167m/s^2
Hey mattwoerd,
It seems you are new to PF. I should tell you something- you are not supposed to solve the whole question in the post. You should only give hints or clear doubts. Read PF rules.
 

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