(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A 40-kg package is at rest on an inlcine when a force P is applied to it. Determine the magnitude of P if 4s is required for the package to travel 10 m up the incline. The static (us) and kinetic (uk) coefficients of friction between the package and the incline are 0.3 and 0.25 respectively.

2. Relevant equations

Newton's 2nd Law : sum of forces = mass x acceleration

x=x0+v0t+0.5at^2

3. The attempt at a solution

First I changed my coordinate system to make the x plane parallel w/ the incline. I then summed the forces in the y direction in equilibrium to find the value of the N, normal force. I found this to be 368.73 N. (N-mgcos(20)=0)

THen I summed the x forces and set equal to mass x acceleration:

Pcos(50)-(uk)(N)=ma

To find a I used the relation x=x0+v0t+0.5at^2:

x-x0 = 10m

v0=0

t=4s

I found a to be 1.25 m/s^2.

Plugging in all the known values I got P = 355.35 N. I know that P is supposed to be 612 N. I was wondering if it was obvious where I was going wrong?

1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

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# Dynamics block problem

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