1. The problem statement, all variables and given/known data A baseball player catching a ball can soften the impact by pulling his hand back. Assuming that a 5-oz ball reaches his glove at 90 mi/h and that the player pulls his hand back during the impact at an average speed of 30 ft/s over a distance of 6 in., bringing the ball to a stop, determine the average impulsive force exerted on the player’s hand. 2. Relevant equations mv1 + Imp1→2 = mv2 v2 = v02 + 2a(x - x0 x = x0 + v0t + 1/2at2 3. The attempt at a solution (o ft/s)2 = (132 ft/s)2 + 2a(6/12 ft) a = -17421 ft/s2 (6/12 ft) = 0 ft + 132 ft/st + 1/2(-17424 ft/s2)t2 t = 0.007575s 0.3125 lbs (132 ft/s) + F(0.007575s) = 0.3125 lbs (0 ft/s) F = 54446 lbs The answer is wayyyy less as it should be.. 76.9 lbs I just can't figure out how to get there..