(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A baseball player catching a ball can soften the impact by pulling

his hand back. Assuming that a 5-oz ball reaches his glove at

90 mi/h and that the player pulls his hand back during the impact

at an average speed of 30 ft/s over a distance of 6 in., bringing the

ball to a stop, determine the average impulsive force exerted on

the player’s hand.

2. Relevant equations

mv_{1}+ Imp_{1→2}= mv_{2}

v^{2}= v_{0}^{2}+ 2a(x - x_{0}

x = x_{0}+ v_{0}t + 1/2at^{2}

3. The attempt at a solution

(o ft/s)^{2}= (132 ft/s)^{2}+ 2a(6/12 ft)

a = -17421 ft/s^{2}

(6/12 ft) = 0 ft + 132 ft/st + 1/2(-17424 ft/s^{2})t^{2}

t = 0.007575s

0.3125 lbs (132 ft/s) + F(0.007575s) = 0.3125 lbs (0 ft/s)

F = 54446 lbs

The answer is wayyyy less as it should be..

76.9 lbs

I just can't figure out how to get there..

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# Dynamics: Impulse and Linear momentum (impulsive force exerted on catchers glove)

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