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Dynamics/Mechanics Question

  1. Oct 9, 2012 #1
    For this question, first I tried finding the speed at which the car is moving at (36.58m/s), but I'm not sure if that's entirely relevant to solving the question.

    The only way the package is moving is from the force applied from the car, so using the formula F = (mv^2)/r, I found that the force to keep the package the same speed as the car is 1503N.

    Then I drew a FBD for the package, and found that in the vertical direction, mu*Nsin60+Nsin30 = mg = 1323. So, therefore mu has to be c (0.3).

    I'm not sure if this is right or not though, any help would be appreciated.
     

    Attached Files:

  2. jcsd
  3. Oct 10, 2012 #2

    Doc Al

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    Staff: Mentor

    That gives you the net force, but what's the full equation for forces in the horizontal direction?
    What's the corresponding equation for the horizontal direction?
     
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