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Dynamics of a cord

  1. May 11, 2014 #1
    1. The problem statement, all variables and given/known data
    Arlene is to walk across a “high wire” strung horizontally between two buildings 10.0 m apart. The sag in the rope when she is at the midpoint is 10.0°, as shown in Fig. 4–47. If her mass is 50.0 kg, what is the tension in the rope at this point?


    2. Relevant equations
    The definitions of sine and cosine.
    [tex]\sum F=ma[/tex]


    3. The attempt at a solution
    I'm really confused by how the tension on the cord could be 1410N, when the rope-walker only exerts a 'weight' of 490N. Evidently, there must be some aspect of cord-tension that I do not understand.
     
    Last edited: May 11, 2014
  2. jcsd
  3. May 11, 2014 #2

    BvU

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    Perhaps there are angles involved... tensions in wires and such can only be in the direction of the wire. Gravity, however, is pulling downwards. Experiment with a weight hnging from a rope you hold with your amrs spread wide.

    Did you learn about decomposing a force in given direction into components in other directions ?
     
  4. May 11, 2014 #3

    SteamKing

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    If you draw a simple sketch of the high-wire artist and the sagged line, and then insert the forces, the solution should become apparent. Remember, at the point where the artist stands on the wire, the sum of the forces in the horizontal and vertical directions must equal zero, since everything is in equilibrium.
     
  5. May 11, 2014 #4
    Ah, thank you. 490/2=245N

    245/sin(10)=1410N.
     
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