# Dynamics Question #5

## Homework Statement

A ball of mass $$0.60kg$$ rolls North at $$4.0ms^{-1}$$. It meets a slope which causes a force of $$0.18N$$ East. This force lasts for $$10s$$. Calculate the final velocity of the ball. Neglect any friction effects.

## Homework Equations

$$F = m.a$$
$$v = u+at$$

## The Attempt at a Solution

$$m = 0.60kg \ , \ v = 4.0ms^{-1} \ , \ F = 0.18N \ , \ t = 10s$$

$$F = m.a$$
$$a = \frac{F}{m} = \frac{0.18}{0.60} = 0.30ms^{-2}$$

$$v = u + at$$
$$v = 4.0 + 0.3 \times 10$$
$$v = 12 ms^{-1}$$

Where did I go wrong?