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Dynamics Question

  1. Jan 13, 2006 #1
    The flat disc rotates around the vertical axis through O a 240rpm (8pi rad/s). each block of 05kg starts of from the spring equilibrium poisition of x = 0.025m. Each spring has stiffness of 400 N/m. Determin the value x and the normal force N of the slot wall on the block. Neglect friction and mass of the springs.
    So far I have.
    [tex] \sum[/tex]F(t) = 0 = Tsin[tex]\theta[/tex] - Ncos [tex]\theta[/tex]
    [tex]\sum[/tex]F(n) = Tcos[tex]\theta[/tex] + Nsin[tex]\theta[/tex] = m.r.[tex]\omega^2[/tex]
    [tex]\sum[/tex]F(y) = N = ma(y) = m.a.sin [tex]\theta[/tex]
    [tex]\sum[/tex]F(n) = T = k(x -0.025)
    r = [tex]\sqrt {0.08^2 + x^2}[/tex]
    My brain has pretty much rotted out on this occassion. Thanks
     

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    Last edited: Jan 13, 2006
  2. jcsd
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