he position of a ball as its kicked upwards is measured as
y(t) =(-4.9 t^2 + 20t + 0.50)m,
where t is measured in seconds. Find the vertical component of velocity and acceleration of the ball as a function of time. If the ground is located at yg = 0, ﬁnd the time at which the ball hits the ground.
Cant I take the first and second derivative to find velocity and acc.? then i don't know how to solve for time
The Attempt at a Solution
would velocity= -9.8t + 20