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Dynamics Question

  • Thread starter FChebli
  • Start date
  • #1
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1. The problem statement

Hey everyone, I'm a new member here... I'd be grateful if you attempt to solve my following question:

A slender rod of length l is pivoted about a point C located at a distance b from its center G. It's released from rest in a horizontal position and swings freely. Determine (a) the distance b for which the angular velocity of the rod as it passes through a vertical position is maximum, (b) the corresponding values of its angular velocity and of the reaction at C.


Homework Equations



KE = T = 1/2 m V2
PE = V = m g h

The Attempt at a Solution



No idea! :S
 

Answers and Replies

  • #2
Doc Al
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I assume that the rod is uniform and that you're just trying to find the optimal pivot point.

Hint: Energy is conserved. How would you express the rotational kinetic energy of the rod?
 
  • #3
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KE = 1/2 I w2?
Do I get the distance b (the distance from point C to the center G of the rod) using PE?
And thank you for the hint...
 
  • #4
Doc Al
Mentor
44,905
1,169
KE = 1/2 I w2?
Right.
Do I get the distance b (the distance from point C to the center G of the rod) using PE?
You'll have to solve for the distance b using the conditions given. The first step is to write an expression for conservation of energy. (Yes, you'll need PE as well as KE.)
 

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