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**1. The problem statement, all varia**

**bles and given/known data**An elevator(4850kg) is to be designed so that the maximum acceleration is 0.068m/s

^{2}. What are the minumum and maximum forces the motor must exert on the supporting cable?

2. Homework Equations

2. Homework Equations

Force = mass(acceleration)

Force

_{vertical}= Ftens + Fgrav

## The Attempt at a Solution

Force

_{vertical}= Ftens + Fgrav

Force = 4850kg(0.068m/s

^{2})

= 329.8N

Force

_{vertical}= 329.8N - 47530N

= -47200N

I'm not so sure about both answers but i think the first solution is kinda right?

thanks in Advance!