1. The problem statement, all variables and given/known data An elevator(4850kg) is to be designed so that the maximum acceleration is 0.068m/s2. What are the minumum and maximum forces the motor must exert on the supporting cable? 2. Relevant equations Force = mass(acceleration) Forcevertical = Ftens + Fgrav 3. The attempt at a solution Forcevertical = Ftens + Fgrav Force = 4850kg(0.068m/s2) = 329.8N Forcevertical = 329.8N - 47530N = -47200N I'm not so sure about both answers but i think the first solution is kinda right? thanks in Advance!