Hey guys, I'm not in any physics class but I found this Advanced Level Physics textbook (its pretty old, printed in 1987) and found it really interesting. So I'm reading along and doing the problems at the ends of each section. Conceptually I understand (most of) everything but I am having a few troubles with some of the problems. Thanks in advance for any pointers in the right direction for any of the problems. Note: I know no Latex. vf = final velocity; vi = initial velocity; % = theta. Feel free to question my syntax so I can clarify any ambiguity. 1. Question: In a nuclear collision, an alphaparticle A of mass 4 units is incident with a velocity v on a stationary helium nucleus B of 4 mass units. After collision, A moves in the direction BC with a velocity v/2, where BC makes an angle of 60 degrees with the initial direction AB, and the helium nucleus moves along BD [there is a diagram where AB is the line/direction where A hits B; BC is the line/direction where A shoots off to going northeast; and BD is where B shoots off to headed southeast]. Calculate the velocity of rebound of the helium nucleus alogn BD and the angle made with the direction AB. My Work: mv + mv = mv + mv x is the velocity of B; v is the velocity of A. X-direction: 4v = 4(v/2)cos60 + 4xcos% 4v - 2vcos60 = 4xcos% 3v = 4xcos% Y-direction: 0 = 4(v/2)sin30 + 4(-x)sin% 2vsin30 = 4xsin% (2vsin30) / (3v) = (4xsine%) / (4xcos%) (2/3)sind30 = tan% % = 18 degrees. I stopped here because... Book's Answer: .9v, 30 degrees. 2. Question: A large cardboard box of mass .75kg is pushed across a horizontal floor by a force of 4.5N. The motion of the box is opposed by (i) a frictional force of 1.5N between the box and the floor, and (ii) an air resistance force kv^2, where k = 6.0 * 10^(-2) kg/m and v is the speed of teh box in m/s. Calculate maximum values for (a) the acceleration of the box, and (b) its speed. My Work: a.) F = ma 4.5 - 1.5 = .75a (why isn't it 4.5 - 1.5 - kv^2 = .75a ?) 3 = .75a a = 4 m/s^s b.) F = ma 4.5 - kv^2 = .75a kv^2 = 1.5 Thats all I have. Book's Answer: (a) 4 m/s^2 (b)7.1 m/s I know this is probably really time consuming for anyone, so thanks again for any help.