It is observed that the ball always bounces exactly once on each step.
s = ut + 1/2at^2
The Attempt at a Solution
So after resolving, horizontal velocity must be always constant as it bounces exactly once on each step and must be 0.30/t ms^-1
So, u*cos(theta) = v*cos(phi) = 0.30(1/t)
And to find e, we form the equation e*u*sin(theta) = -v*sin(phi)
I also find time t, for which the ball moves -0.20m vertically and 0.30m horizontally. Upwards as positive. Using s = ut + 1/2at^2
-0.20 = v*sin(phi)*t + 1/2(-9.81)(t^2)
But I tried manipulating around and I just can't find e.
Is something wrong with my method? Do I need to use momentum to calculate this question?
Last edited by a moderator: