A Charge of 3.2x10-6 sits .025 m from a charge of -1.6x-6 a. Calculate the magnitude and direction of the E-filed at a point directly between the 2 charges b. calculate the electric potential (relative to V = 0 at infinity) at the point directly between the two charges c. Calculate the work needed to bring a 1x10-6 charge from infinity to the point between the two charges 19. A 2000 V/m electric field is directed along the +x-axis. If the potential at x = 10 m is 800 V, what is the potential at x = 6m? A. 8800V B. 2000V C. 7200V D. 1600V 2. Relevant equations F = kqQ/r2 V= w/q 3. The attempt at a solution a. F=9x10^9*-1.6x10^-6/.025^2 =-73.728 N b. I don't know, v=w/q uses only one charge, and I don't know any other formulas. Some sort of clue, a formula, would be great c. I think if I knew how to do part b I could do part c 19. I know that as you get closer, the potential increase, so the answer can't be B or D. However, I don't know any formula that could tell me how to find the answer. Help please?