- #1

- 51

- 0

^{-6}sits .025 m from a charge of -1.6x

^{-6}

a. Calculate the magnitude and direction of the E-filed at a point directly between the 2 charges

b. calculate the electric potential (relative to V = 0 at infinity) at the point directly between the two charges

c. Calculate the work needed to bring a 1x10

^{-6}charge from infinity to the point between the two charges

19. A 2000 V/m electric field is directed along the +x-axis. If the potential at x = 10 m is 800 V, what is the potential at x = 6m?

A. 8800V

B. 2000V

C. 7200V

D. 1600V

## Homework Equations

F = kqQ/r

^{2}

V= w/q

## The Attempt at a Solution

a. F=9x10^9*-1.6x10^-6/.025^2

=-73.728 N

b. I don't know, v=w/q uses only one charge, and I don't know any other formulas. Some sort of clue, a formula, would be great

c. I think if I knew how to do part b I could do part c

19. I know that as you get closer, the potential increase, so the answer can't be B or D.

However, I don't know any formula that could tell me how to find the answer.

Help please?