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E^-ln(x) = 1/x?

  1. Sep 10, 2013 #1

    1s1

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    1. The problem statement, all variables and given/known data

    Is ##e^{-ln(x)}## equal to ##\frac{1}{x}## ?

    2. Relevant equations



    3. The attempt at a solution

    ##e^{-ln(x)} = e^{ln(x^{-1})} = e^{ln(\frac{1}{x})} = \frac{1}{x}## ?

    Thanks!
     
  2. jcsd
  3. Sep 10, 2013 #2

    Zondrina

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    Homework Helper

    Yes that is correct. It's a very common mistake that I see to not apply the log rules before eliminating ##e## and ##ln##.
     
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