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## Homework Statement

Is ##e^{-ln(x)}## equal to ##\frac{1}{x}## ?

## Homework Equations

## The Attempt at a Solution

##e^{-ln(x)} = e^{ln(x^{-1})} = e^{ln(\frac{1}{x})} = \frac{1}{x}## ?

Thanks!

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- Thread starter 1s1
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- #1

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Is ##e^{-ln(x)}## equal to ##\frac{1}{x}## ?

##e^{-ln(x)} = e^{ln(x^{-1})} = e^{ln(\frac{1}{x})} = \frac{1}{x}## ?

Thanks!

- #2

STEMucator

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## Homework Statement

Is ##e^{-ln(x)}## equal to ##\frac{1}{x}## ?

## Homework Equations

## The Attempt at a Solution

##e^{-ln(x)} = e^{ln(x^{-1})} = e^{ln(\frac{1}{x})} = \frac{1}{x}## ?

Thanks!

Yes that is correct. It's a very common mistake that I see to not apply the log rules before eliminating ##e## and ##ln##.

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