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Homework Statement
Is ##e^{-ln(x)}## equal to ##\frac{1}{x}## ?
Homework Equations
The Attempt at a Solution
##e^{-ln(x)} = e^{ln(x^{-1})} = e^{ln(\frac{1}{x})} = \frac{1}{x}## ?
Thanks!
Yes that is correct. It's a very common mistake that I see to not apply the log rules before eliminating ##e## and ##ln##.Homework Statement
Is ##e^{-ln(x)}## equal to ##\frac{1}{x}## ?
Homework Equations
The Attempt at a Solution
##e^{-ln(x)} = e^{ln(x^{-1})} = e^{ln(\frac{1}{x})} = \frac{1}{x}## ?
Thanks!