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E^-ln(x) equation

  1. Jan 31, 2009 #1
    1. The problem statement, all variables and given/known data

    is e^-ln(x) the same as 1/x ??

    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Jan 31, 2009 #2

    cristo

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    Re: e^-ln(x)

    What do you think?
     
  4. Jan 31, 2009 #3

    symbolipoint

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    Re: e^-ln(x)

    What do you know about numbers and exponents to those numbers?

    Let t be any real number. What can you do with e[tex]^{-t}[/tex] ?
     
  5. Jan 31, 2009 #4

    jgens

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    Re: e^-ln(x)

    Well perhaps a way of verifying your answer would be to note -ln(x) = ln(1/x); therefore, e^-ln(x) = e^ln(1/x). Another way is to note e^-ln(x) = 1/e^ln(x).
     
  6. Jan 31, 2009 #5

    cristo

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    Re: e^-ln(x)

    Recall:
     
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