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E&M capacitors

  1. Nov 4, 2007 #1
    Two identical, oppositely-charged, conducting plates of area 2.50cm² are separated by a dielectric 1.80 mm thick, with a dielectric constant of 3.60. The resultant electric field in the dielectric is 1.2*10^6 V/m.

    a)Compute the charge per unit area on the conducting plate.
    b)Compute the charge per unit area on the surfaces of the dielectric.

    3. The attempt at a solution
    for part a). I used gauss's law for dielectric.
    Q/A = K*epsilon_0*E = 3.60*8.85*10^-12*1.2*10^6 = 3.82*10^-5 C/m² which is correct.

    However i haven't got a single clue how to do part b. But the answer is suppose to be 2.76*10^-5 C/m². Can someone please help me figure out how this answer was obtained?
     
  2. jcsd
  3. Nov 5, 2007 #2

    Meir Achuz

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    For b, they must mean bound surface charge density, which equals the normal component of the polarization vector P.
     
  4. Nov 5, 2007 #3
    thank you for help. i managed to figure it out now with your tip :)
     
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