A particle of charge 5.03 nC is placed at the origin of an
A second particle of charge -2.00 nC is placed on the positive x-axis at x = 4.04 cm.
A third particle, of charge 6.01 nC is now placed at the point x = 4.04 cm, y = 3.00 cm.
Find the x-component of the total force exerted on the third charge by the other two.
Find the y-component of the total force exerted on the third charge by the other two.
Find the magnitude of the total force acting on the third charge.
Find the direction of the total force acting on the third charge in radians.
Coulomb's Law = k(q1q2)/r^2
The Attempt at a Solution
The answers I got were
Fx = 6.38*10^-5
Fy = -3.49*10^-5
Direction was .944 radians
all of which were wrong. I don't know how to calculate the Ftotal, or what I did wrong.