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E = 1/2MV^2

I found the equation strikingly similar to Einsteins famous equation E=MC^2

The only real difference is the 1/2 coefficient (Since C is just a constant for V)

So i figured there should be a constant for V in the kinetic energy equation that would make the two equations yield the same result so...

mc^2 = 1/2mv^2

assume a value of 1 for the mass

c^2 = 1/2v^2

sqrt(2c^2) = v

v = 423,970,560 m/s

So by substituting the constant 423,970,560 m/s (call it 'Q') into velocity for the kinetic energy equation the two equations become equivalent.

E = mc^2 = 1/2mq^2

So basically any mass moving at the velocity 423,970,560 m/s will have the same kinetic energy as the energy contained in the mass at rest as described by E = MC^2. Which made me wonder if perhaps the reason all mass at rest has this energy is because the universe is rotating or moving at velocity Q?

Which brings me to my question..

Is there a explanation as to why E = MC^2?