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E=mc^2 Confusion

  1. Nov 19, 2006 #1
    "I beleive E=mc^2 works." But!
    Photon (Packet of energy as described by Einstein in 1905, "Photoelectric effect") is mass less particle. So, the relation suggests that light should not have energy, though it has.

    Is this wrong, if yes why?
     
  2. jcsd
  3. Nov 19, 2006 #2
    It is nothing wrong. If a photon had a "nonzero resting mass", its "c speed traveling mass" would be infinite.

    But it isn't.
     
  4. Nov 19, 2006 #3
    [itex]E={m_0}{c^2}[/itex] where [itex]m_0[/itex] is the rest mass. Since energy and mass are equivalent, when a particle moves it gains mass, even if its rest mass is zero, like a photon.

    For an object in motion there is, where p is the momentum, [itex]{E^2}={{m_0}^2}{c^4}+{p^2}{c^2}[/itex], so the photon's energy (with it's zero rest mass) is [itex]E=pc[/itex]
     
    Last edited: Nov 19, 2006
  5. Nov 19, 2006 #4
    No. [itex]E={m}{c^2}[/itex] where m is the relativistic mass.

    You can understand that E is not [itex]{m_0}{c^2}[/itex], for a moving particle, from the correct equation you wrote then:

    [itex]{E^2}={{m_0}^2}{c^4}+{p^2}{c^2}[/itex]

    If it were [itex]E={m_0}{c^2}[/itex], substituting this value in the previous equation, you would have:

    [itex] {{m_0}^2}{c^4} ={ {m_0}^2}{c^4} +{p^2}{c^2}[/itex]

    that is: p = 0, which implies v = 0, so the particle is necessarily at rest.
     
    Last edited: Nov 19, 2006
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