The energy of any piece of matter is given by E = mc^2 + Relative Energy Usuall the relative energy term is 1/2mv^2 thus for v << c E = mc^2 + 1/2mv^2, but what if this particle was 100K As opposed to 0K does temperature play a role in the energy of an object using this definition? If so wouldn't a better definition of energy be given by E = Inertial Energy + Relative Energy if it was of this form, it would almost be like the Basic Kinematic Equation which states that the acceleration between two systems can be found by finding the relative acceleration added to any corrective terms due to various types of gyroscopic motion. Thus, energy would be the same way. Meaning no object as absolute energy, it is all relative depending on differences in velocity, temperature, and potentials between 2 observers. Does anyone agree?