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E-powers homework help

  1. Nov 29, 2005 #1
    why does e^[i(phi)] * e^[-i(phi)]=1 instead of e^[(phi)^2]?
     
  2. jcsd
  3. Nov 29, 2005 #2

    TD

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    Well for powers, so for e-powers in particular, we have that [itex]e^a \cdot e^b = e^{a + b}[/itex]. Applying that here gives e^0 which is of course 1.
     
  4. Nov 30, 2005 #3
    thank you very much!!!
     
  5. Nov 30, 2005 #4

    TD

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    No problem :smile:
     
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