E|X|=E(X) ?

[torquerotates]

Is this true?


In all cases?

 

[WendyE]

E(X) = expectation of X

Let X = {-1, 0, 1}
E(X) = (-1+0+1)/3 = 0

E|X| = ( |-1|+|0|+|1| )/3 = (1+0+1)/3 = 2/3

So, I think no, it's not true that E|X| = E(X) if I understand the question correctly.