A resistor and inductor are connected in series to a battery. The current in the circuit ( in A ) is given by I = 2.7(1-e-0.1), where t is the time since the circuit was closed. By using the series for ex, find the first three terms of the expansion of this function.
ex = 1 + x + x2/2! + ... + xn/n!
The Attempt at a Solution
Would I substitute -0.1 for x in this expansion like so: ex = 1 - 0.1 - 0.12/2! ? And then place this expansion into the original function 2.7(1-(1 - 0.1 - 0.12/2!)) ?? And finally, multiply the 2.7 back in?
This isn't coming out to one of my answer choices. Where have I gone wrong in my setup?