E^y + e^-y =2x or e^2y - 2xe^y + 1 = 0 equation

  • #1
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Main Question or Discussion Point

In this textbook i am looking at it says:

"Thus e^y + e^-y =2x or

e^2y - 2xe^y + 1 = 0"

how did they go from the first to the second part?
 

Answers and Replies

  • #2
Hurkyl
Staff Emeritus
Science Advisor
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Well, look at pieces of the equation and see if that gives you any clues.

For example, their second equation has an e^(2y) in it1. Can you think of anything to do to the first equation so that the result will have an e^(2y) in it?

1: I assume you meant e^(2y) and not e^2y (which is the same as (e^2)y)
 
  • #3
You should really try to figure this out yourself. What's the difference between the two equations?
 
  • #4
187
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i still dont get how to go from

[tex]e^y + exp(-y)=2x[/tex]

to

[tex]e^2y - 2xe^y + 1 = 0[/tex]

help please
 
  • #5
81
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I'm not sure, but that y should be raised too....e^(2y) not (e^2)y
 
  • #6
Hurkyl
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Have you tried any of our hints?
 

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