1. The problem statement, all variables and given/known data I'm just having a little difficulty understanding this E2 reaction. 3. The attempt at a solution Okay, so I know that this is a one step reaction. Br is the base, but does water (the solvent) have effect on the reaction? I just assumed the Bromide would attack the H in the lower right of the ring, the electron density would transfer to the double bonded Carbon, and the double bonded carbon would split so that it doesn't have a (-) charge. I just don't know whether it's just Br that binds or Br and OH bind in the ring.