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E2 Reactions

  1. Nov 18, 2012 #1
    1. The problem statement, all variables and given/known data
    I'm just having a little difficulty understanding this E2 reaction.

    3. The attempt at a solution

    Okay, so I know that this is a one step reaction. Br is the base, but does water (the solvent) have effect on the reaction? I just assumed the Bromide would attack the H in the lower right of the ring, the electron density would transfer to the double bonded Carbon, and the double bonded carbon would split so that it doesn't have a (-) charge. I just don't know whether it's just Br that binds or Br and OH bind in the ring.
     

    Attached Files:

  2. jcsd
  3. Nov 18, 2012 #2
    My mistake. It's an E1 reaction.. so the H2O solvent is protic, would it be IV?
     
  4. Nov 19, 2012 #3

    AGNuke

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    Gold Member

    It is NOT an elimination reaction. Br2 is NOT a base.

    Br2 will polarize to form Br+, which is an electrophile and will attack on double bond, followed by nucleophilic attack of water.
     
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