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[PLAIN]http://img37.imageshack.us/img37/2208/43252578.jpg [Broken]

Ok so

i did this questions and was satisfied with my answer, but some guy rekons i did it wrong so i just want to double check

First i found the total capacitance, so i got 1/12 + 1/12 = 1/6 = 6 (for the series in the paralell)

then added that series to the paralell capacitor, 6+12 = 18

then added that in series to the final capacitor 1/18+1/12 = blah = 7.2

so the total capacitance is 7.2, to find the charge i times it by the voltage

7.2 x 12 = 86.4

then with this i found the voltage through the paralel circuit, 86.4/18 = 4.8

then the same with the lone capacitor 86.4 / 12 = 7.2

7.2 + 4.8 = 12

so voltage in = voltage out... is that a correct rule ? thats what he said i did wrong

that voltage in doesnt = voltage out

but with that

i halfed 4.8 because they're paralell , so 2.4 on the top part and 2.4 on the bottom part of the paralell circuit

and the lone capacitor has a V = 7.2

does that all seem right? or is voltage in not supposed to equal voltage out?

the guy got like 6 6 3 3 for his voltages which is 18V total

i dono it doesnt seem right to me at all but im probably wrong

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# Homework Help: Easy Capacitor problem

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