(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Solve x.dy/dx+1-y^2=0

2. Relevant equations

3. The attempt at a solution

Separate:

dy/(y^2-1) = dx/x

The LHS can be broken into

dy/(2(y-1))-dy/(2(y+1))

Integrating:

Log[y-1]/[y+1] = log[x^2] + c

Given x=1 when y=0 c=0

Y-1=x^2.y+x^2

Y=(x^2+1)/(x^2-1)

The answer is the reciprocal of mine, can anyone see my mistake?

Thanks

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# Easy differential equation

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