- #1

- 77

- 0

Factorize:

x^3 − 2x^2 − 4x + 8 correct answer:

(x^3 − 2x^2) − (4x − 8)

x^2(x − 2) − 4(x − 2)

(x − 2)(x + 2)(x − 2)

(x − 2) 2(x + 2)

In the third line where the terms are grouped i don't understand why one of the (x - 2) is omitted? i.e shouldn't it be (x -2)^2 ?

x^3 − 2x^2 − 4x + 8 correct answer:

(x^3 − 2x^2) − (4x − 8)

x^2(x − 2) − 4(x − 2)

**(x^2 − 4)(x − 2)**(x − 2)(x + 2)(x − 2)

(x − 2) 2(x + 2)

In the third line where the terms are grouped i don't understand why one of the (x - 2) is omitted? i.e shouldn't it be (x -2)^2 ?

Last edited: