a boy whirls string of length 2 metres around in a horizontal plane. At the end of the string a mass of M2 = 0.1kg is tied while at 1m (midway on the string) another mass M1 = 0.1Kg is fastened. The boy increases angular velocity [tex] \omega [/tex] in the motion of the string. The hand of the boy and the two masses will, when omega is sufficiently large, be almost on a straight line. When the string force reaches 327N the string will break.(adsbygoogle = window.adsbygoogle || []).push({});

Find the magnitude of the angular velocity when the string breaks and find where the break occurs.

Since maximum of the tension on the string will be between the boy's hand and the mass m1 the string will break right there. Also since they are almost in a horizontal circle the angular velocity is common.

when [tex] T = 327 N = m_{1} \omega^2 r_1 + m_2 \omega^2 r_2[/tex]

which gives [tex] 327 = 0.1 * \omega^2 * 1 + 0.1 * \omega^2 * 2[/tex]

and this yields 33.02 / s

Is it possible to whirl the two masses in such a way that the two masses on the string are exactly on a horizontal line?

I would think that when the two omegas are the same the string will break so is it not possible

i ned more help with actualyl explaining the second one. Also i need explanations because my prof is like that. Are my explanatuons concise enough or do i need any more detail.

your suggestions and help are appreciated!

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# Homework Help: Easy kinematics question

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