# Easy math problem

1. Apr 15, 2013

### bmed90

So if

Equation: X=Xo*[e^(ln^2)/Td] * T

with

X = 5e12
Td = 15
T= 672

My question: is how do I evaluate (ln^2) ??
Usually when I use the ln function to calculate something its like ln(5/2)^2 or something like that but here its just ln^2

what does this mean? How do you get 17 for Xo

2. Apr 15, 2013

### pwsnafu

Wait $\ln ^2$? That's not defined. Maybe it should be just ln(2)

3. Apr 15, 2013

### bmed90

I used ln(2) but that did not give me an answer of 17

4. Apr 15, 2013

### bmed90

Nvm I got. Thanks

5. Apr 15, 2013

### DeeAytch

I think it would have funny if you had posted some unproven conjecture and then moments later posted "nvm, got it."

Just a thought..