Easy math quesiton

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3(x^2)=a^2

When are a and x whole integers?
 

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HallsofIvy
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In what sense does this have anything to do with "Tensor Analysis and Differential geometry"? I'm moving it to "number theory".

In any case, if 3x2= a2 for a and x integers, then we must have
[itex]a= x\sqrt{3}[/itex] which is impossible unless x= a= 0. It implies [itex]\sqrt{3}= a/x[/itex] but [itex]\sqrt{3}[/itex] is irrational.

The only integer solution to 3x2= a2 is x= a= 0.
 

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