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Easy momentum/ kenitic

  1. Mar 23, 2009 #1
    I know that :

    kinetic energy of something = P^2 / 2m , or momentum squared over 2m

    why so?

    I see that taking the integral of mv dv = kenitic.

    can you prove this to
  2. jcsd
  3. Mar 23, 2009 #2

    Vanadium 50

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    You know p in terms of m and v. You also know E in terms of m and v. This should get you started.
  4. Mar 23, 2009 #3
    KE = [tex]\frac{1}{2} mv ^ 2[/tex]

    = [tex]\frac{1}{2} pv[/tex]

    = [tex]\frac{1}{2} \frac{pmv}{m}[/tex]

    = [tex]\frac{1}{2} \frac{p ^ 2}{m}[/tex]
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