3z/2=z/6+4 so i x multiply and get 18z=2z+8 16z=8 z=1/2 this look right? thanks
Apr 12, 2005 #1 thomas576 20 1 3z/2=z/6+4 so i x multiply and get 18z=2z+8 16z=8 z=1/2 this look right? thanks
Apr 12, 2005 #2 arildno Science Advisor Homework Helper Gold Member Dearly Missed 10,106 136 Unfortunately no; you forgot to multiply your constant with 6 as well (with the "constant", I mean the lone "4" in your original equation)
Unfortunately no; you forgot to multiply your constant with 6 as well (with the "constant", I mean the lone "4" in your original equation)
Apr 12, 2005 #4 arildno Science Advisor Homework Helper Gold Member Dearly Missed 10,106 136 3z/2=z/6+4 1. Multiply both sides of the equation with 6: 6*(3z/2)=6*(z/6+4) OR: 18z/2=6z/6+6*4 Or: 9z=z+24 That is: 8z=24 Whereby: z=3 Note: I didn't bother with your cross-multiplication; that was an unnecessary operation.
3z/2=z/6+4 1. Multiply both sides of the equation with 6: 6*(3z/2)=6*(z/6+4) OR: 18z/2=6z/6+6*4 Or: 9z=z+24 That is: 8z=24 Whereby: z=3 Note: I didn't bother with your cross-multiplication; that was an unnecessary operation.