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I have a very simple complex arithmetic question.

How do I express the quantity cos(1+i) in Cartesian (a+ib) and Euler(re^i*theta)

Is this the right track?:

[tex]cos(1+i)={e^{i(1+i)}\over2}+{e^{-i(1+i)}\over2}[/tex]

I know that:

[tex]cos(1+i)=cos(1)cos(i)-sin(1)sin(i)[/tex]

but I am not sure how to get the "i's" out of the cosine and sine.

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# Homework Help: Easy Peasy CA problem

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