# Easy Pre-Calc Question - Natural Logs

1. Oct 11, 2004

### sjaguar13

$$e^{-x^2}=(e^x)^3(\frac{1}{e^4})$$

Wouldn't all the Es cancel out?
$$-x^2=3x-4$$

Move the 3x and factor out a -x:
$$-x(x+3)=-4$$

Now I got nothing.

2. Oct 11, 2004

### vsage

try moving the -x^2 over to the right side.

3. Oct 11, 2004

### sjaguar13

OHHHH....
$$0=-x^2+3x-4$$

Do a little factorin'
$$(x+4)(x-1)$$

$$x=-4 or x=1$$

Both of those are the answer, right, or is there a restriction on x?