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How much work is needed to move a proton from a point with a potential of +630V to a point where it is -60.0V?
Ok so wouldn't I just use the equation:
(Va-Vb)=Wba/q
(-60-630)=Wba/(1.6 x 10^-19)
Wba=-1.104 x 10^-16 J
Ok so wouldn't I just use the equation:
(Va-Vb)=Wba/q
(-60-630)=Wba/(1.6 x 10^-19)
Wba=-1.104 x 10^-16 J