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Easy question on relativity

  1. Oct 12, 2004 #1
    Through waht potential difference must a proton be accelerated in order to reach a speed of 4/5 c?? Answer in volts.

    Since (in relativisitic terms) K = mc^2 (gamma -1)

    then q dV = mc^2 (gamma -1 )

    where dV is the potential difference

    and q is the charge of the proton = 1.6 e -19 V

    Am i right?? please do tell!
     
  2. jcsd
  3. Oct 13, 2004 #2

    Tide

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    Good start! Just be careful with your units for charge - it is not measured in volts.
     
  4. Oct 13, 2004 #3
    the answer is required in volts, however
     
  5. Oct 13, 2004 #4

    Tide

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    Yes, but you wrote the charge in units of Volts.
     
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